Answer:
the estimate distance moved by the car will be equal to 42 m
Step-by-step explanation:
Using second degree polynomial
[tex]y(t) =y_0+ y'_0(x-a)+y''_0\dfrac{(x-a)^2}{2}\\[/tex]
given,
y'₀ = 40 m/s y''₀ = 4 m/s²
at t = 0 y₀ = 0
[tex]y(t) = 40\times t+ \dfrac{t^2}{2}\times 4\\y(t) = 40t+ 2 t^2[/tex]
at t =1
y(1) = 40 ×1 + 2× 1²
y(1) = 42 m
hence, the estimate distance moved by the car will be equal to 42 m