Respuesta :
Explanation:
As it is given that both have same dynamic characteristics.
Therefore, [tex]Re_{water}[/tex] = [tex]Re_{CCl_{4}}[/tex]
[tex]\frac{\rho_{water} \times \nu_{water} \times D_{water}}{\mu_{water}}[/tex] = [tex]\frac{\rho_{CCl_{4}} \times \nu_{CCl_{4}} \times D_{CCl_{4}}}{\mu_{CCl_{4}}}[/tex]
Hence, putting the given values into the above formula as follows.
[tex]\frac{998 kg/m^{3} \times 2 m/s \times 50 mm}{10^{-3}Pa.s}[/tex] = [tex]\frac{1590 kg/m^{3}} \times \nu_{CCl_{4}} \times 60 mm}{0.958 \times 10^{-3}}[/tex]
[tex]\nu_{CCl_{4}}[/tex] = 1.002 m/s
Thus, we can conclude that the velocity of carbon tetrachloride in the given conditions is 1.002 m/s.
