Respuesta :
Answer:
[tex]K_b=\frac {[(CH_3)_2{NH_2}^+][OH^-]}{[(CH_3)_2NH]}[/tex]
Explanation:
Kb is base dissociation constant which is measure of the dissociation of a base into component ions in the water.
The base, (CH₃)₂NH dissociates in water as:
(CH₃)₂NH (aq) + H₂O (l) ⇄ (CH₃)₂NH₂⁺ (aq) + OH⁻ (aq)
The expression for Kb is:
[tex]K_b=\frac {[(CH_3)_2{NH_2}^+][OH^-]}{[(CH_3)_2NH]}[/tex]
Water is present in large amounts and is not written in the expression for Kb.
The study of chemicals is called chemistry.
The correct answer is [tex]Kb = \frac{(Ch_3)_2NH_2^+}{(CH_3)_2NH}[/tex]
What is dissociation constant?
- Kb is the base dissociation constant which is a measure of the dissociation of a base into component ions in the water.
The reaction involved in the question is as follows:-
[tex](CH_3)_2NH (aq) + H_2O (l) <---->(CH_3)_2NH_2^+ (aq) + OH^- (aq)[/tex]
Hence, the expression of the Kb is [tex]Kb = \frac{(Ch_3)_2NH_2^+}{(CH_3)_2NH}[/tex]. With the help of this equation, we can find the kb of the equation
Hence, we can conclude that the above expression can help us to find the Kb of the weak base in an equilibrium state.
For more information about the equilibrium constant, refer to the link:-
https://brainly.com/question/10038290
