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For a person with a Near Point (NP) = 45 cm, what would be his prescription's lens power = _________ diopters A) 1.08 diopters B) 2.842105 diopters C) 1.778 diopters D) 0.54 diopters E) 0.225 diopters

Respuesta :

Answer:

The power of lens is 2.22 D.

Explanation:

Given that,

Distance of image v= 45 cm

We know that,

Distance of object u= ∞

Power of lens is the reciprocal of focal length.

[tex]P=\dfrac{1}{f}[/tex]

We need to calculate the power of lens

Using formula of lens

[tex]\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}[/tex]

Where, f = focal length

v = image distance

u = object distance

Put the value into the formula

[tex]\dfrac{1}{f}=\dfrac{1}{45}+\dfrac{1}{\infty}[/tex]

[tex]\dfrac{1}{f}=\dfrac{1}{0.45}+0[/tex]

[tex]P=\dfrac{1}{f}=2.22[/tex]

Hence, The power of lens is 2.22 D.

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