Can somebody help me out with this? I don’t understand and it’s due in an hour

Answer:
[tex]\large\boxed{y=\dfrac{1}{18}x-\dfrac{2}{3}}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the equation in the standard form (Ax + By = C).
Convert to the slope-intercept form:
[tex]x-18y=12[/tex] subtract x from both sides
[tex]x-x-18y=12-x[/tex]
[tex]-18y=12-x[/tex] divide both sides by (-18)
[tex]\dfrac{-18y}{-18}=\dfrac{12}{-18}+\dfrac{-x}{-18}\\\\y=-\dfrac{12}{18}+\dfrac{x}{18}\\\\y=\dfrac{1}{18}x-\dfrac{12:6}{18:6}\\\\y=\dfrac{1}{18}x-\dfrac{2}{3}[/tex]