Answer:
The mass composition of ∝ ferrite is 88.94%.
The mass composition of cementite is 11.05%.
Explanation:
Given that
T=726 °C
We have to find the mass fractions of ferrite nad cementite in pearlite.
Lets take data from ideal Iron -carbon diagram at 726 °C
Composition of ∝ ferrite=0.022 5
Composition of pearlite =0.76 %
Composition of cementite =7.6%
We know that if we want to find the mass fraction the we use Lever rule .So now by using lever rule
[tex]The\ mass\ composition\ of\alpha \ ferrite =\dfrac{6.7-0.76}{6.7-0.022}[/tex]
So the mass composition of ∝ ferrite is 88.94%.
[tex]The\ mass\ composition\ of\ cementite =\dfrac{0.76-0.022}{6.7-0.022}[/tex]
So the mass composition of cementite is 11.05%.
Based on the proportion of ferrite and cementite in pearlite, the following are true:
= (Percentage cementite - Percentage of Co) / ( Percentage of cementite - Percentage of ferrite)
= (6.7% - 0.76%) / (6.7% - 0.022%)
= 5.94% / 6.678%
= 0.8895
= (Percentage Co- Percentage of Ferrite) / ( Percentage of cementite - Percentage of ferrite)
= (0.76% - 0.022%) / (6.70% - 0.022%)
= 0.738 / 6.678
= 0.11051
Find out more on Cementite at https://brainly.com/question/16034772.
