contestada

A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in _____ cm? a. -8 cm b. -4 cm c. -5 cm d. -2 cm

Respuesta :

Answer:

a. -8 cm

Explanation:

[tex]d_{o}[/tex] = distance of the object = 4 cm

[tex]d_{i}[/tex] = distance of the image = ?

[tex]f[/tex] = focal length of the converging lens  = 8 cm

using the lens equation

[tex]\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}[/tex]

[tex]\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}[/tex]

[tex]d_{i}[/tex] = - 8 cm