Respuesta :
Answer:
d = 0.67 m
Explanation:
Initial speed of the car is given as
[tex]v_i = 2.0 m/s[/tex]
final speed of the car after which it will stop is given as
[tex]v_f = 0[/tex]
now the deceleration of the car which is due to brakes is given as
[tex]a = - 3 m/s^2[/tex]
now the distance after which it will stop is given as
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
[tex]0 - 2^2 = 2(-3)d[/tex]
[tex]d = \frac{4}{6} m[/tex]
[tex]d = 0.67 m[/tex]
The distance traveled before the car stop will be 0.67 m.
What is velocity?
The change of distance with respect to time is defined as velocity. Velocity is a vector quantity. Its unit is m/sec.
Given data in problem is,
Initial speed,u=2 m/sec
Final speed,v= 0 m/sec
Deceleration of the car,a = - 3 m/sec²
Distance traveled before the car stop,s
The distance traveled before the car stop is found as,
v²=u²+2as
0²=2²+2(-3)s
s = 4/6
s =0.67 m
Hence, the distance traveled before the car stop will be 0.67 m.
Learn more about Velocity here;
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