Answer:
i) 1920 W
ii) 230.4 kWh
iii) $23.04
Explanation:
i = steady current drawn = 16.0 A
V = Voltage of the power supply = 120 Volts
T = Time of operation per day = 4 h
n = number of days = 30
t = total time spent during operation = n T = (30) (4) = 120 h
i)
Power consumed by heater is given as
P = i V
P = (16) (120)
P = 1920 Watt
ii)
Energy consumed is given as
E = P t
E = (1920) (120)
E = 230400 Wh
E = 230.4 kWh
iii)
c = charge per kW of electricity = 10 cents
C = Total cost
Total cost is given as
C = c E
C = (10) (230.400)
C = $23.04