Respuesta :
Answer:
C. E/2, F.
Explanation:
Suppose two particles as A and B which are separated by a distance of r.
And the charge on the particle A is +2q and the charge on the particle B is +q.
According to the question, the electric field at a distance of r on the charge +2q is E.
[tex]E=\dfrac{2q}{4\pi\epsilon{0}r^2 }[/tex].
And the force on the +q charge at a distance of r is F.
[tex]F=\dfrac{(q)(2q)}{4\pi\epsilon{0}r^2 }[/tex].
Now, the electric field can be calculated at +q charge on the same distance will be,
[tex]E'=\dfrac{q}{4\pi\epsilon{0}r^2 }.[/tex]
Now substitute E/2 for [tex]\dfrac{q}{4\pi\epsilon{0}r^2 }[/tex] in the above equation will get,
E'=E/2.
Therefore the electric field at distance r on +q charge is E/2.
Now the force xcan be calculated at the distance r on charge +2q will be
[tex]F'=\dfrac{(q)(2q)}{4\pi\epsilon{0}r^2 }[/tex]
Substitute F for [tex]\dfrac{(q)(2q)}{4\pi\epsilon{0}r^2 }[/tex] in the above equation will give,
F'=F.
Therefore, the force exert on the +2q charge at the distance r will be F.
