Respuesta :
Answer:
The correct answer for the given question is option(A) i.e its value is copied into the method's parameter variable.
Explanation:
Following are the points regarding that.
1.In function calling when we use call by value the actual argument is passed to the formal argument .
2.The actual argument are those which is present in the calling portion of the program.
3.The formal parameter are those which is present in method signature.
4.It means that The value of actual argument is copy into the formal argument i.e method's parameter.
5.Let us consider an example
Following are the code in C++
#include<iostream>// header file
using namespace std;
void sum(int,int);
int main() // main function
{
int a=90,b=9; // variable declaration
sum(a,b);//here a and b are actual parameter calling function sum
return 0;
}
void sum(int p,int q) // function definition
{
cout<<" the sum is :"<<p+q; // add
}
In this program the actual parameter is a and b and method parameter is p and q respectively.
The variable a "actual parameter" is copies the value in variable p "formal parameter".Similarly the variable b "actual parameter" is copies the value in variable p "formal parameter".So changes made in formal parameter does not reflected back to actual parameter this is call by value which copies the value of actual parameter to method parameter.
output:99
Therefore The correct option is(A).
