Answer:
(C) 4 beats per second.
Explanation:
As we know that the no of beats can be calculated as.
No. of beats is equal to difference in the tuning forks frequencies.
So,
[tex]n= \nu _{1}- \nu _{2}[/tex].
Substitute the values of frequencies of 2 tuning forks in the above equation.
[tex]n=(260 Hz-256 Hz)\\n=4[/tex]
Therefore the number of beats per second will be hear by the observer is 4 beats per second.
