Respuesta :
Answer:
Charge, [tex]q=1.32\times 10^{-5}\ C[/tex]
Explanation:
It is given that,
Capacitance, [tex]C=2.2\ \mu F=2.2\times 10^{-6}\ F[/tex]
Voltage, V = 6 volts
We need to find the charge held by the capacitor. It is given by :
[tex]q=C\times V[/tex]
[tex]q=2.2\times 10^{-6}\ F \times 6\ V[/tex]
q = 0.0000132 C
or
[tex]q=1.32\times 10^{-5}\ C[/tex]
So, the charge held by the capacitor is [tex]1.32\times 10^{-5}\ C[/tex]. Hence, this is the required solution.
Answer:
13.2\mu C
Explanation:
The capacitance of the capacitor C = 2.2 microfarad [tex]=2.2\times 10^{-6}F[/tex]
Voltage at the capacitor =6 V
The charge on the capacitor is equal to the product of capacitance and the voltage , so charge = capacitance ×voltage
So charge [tex]Q=CV=2.2\times 10^{-6}\times 6=13.2\times 10^{-6}C=13.2\mu C[/tex]
