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At one point in space the Electric potential is measured to be 119 V at a distance of 1 meters away it is measured to be 43 V. Find the magnitude electric field.

Respuesta :

Answer:

76 V/m

Explanation:

[tex]V_{i}[/tex] = Electric potential at initial location = 119 V

[tex]V_{f}[/tex] = Electric potential at final location = 43 V

[tex]d[/tex] = distance between initial and final location = 1 m

[tex]E[/tex] = magnitude of electric field

Magnitude of electric field is given as

[tex]E = \frac{- (V_{f} - V_{i})}{d}[/tex]

[tex]E = \frac{- (43 - 119)}{1}[/tex]

[tex]E[/tex] = 76 V/m

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