Answer:
The energy dissipated is 1.754 J.
Explanation:
Given that,
Mass of hockey = 0.167 Kg
Initial velocity = 5.45 m/s
Finally velocity = 2.95 m/s
We need to calculate to the energy dissipated over the rough patch = loss in kinetic
[tex]E_{d}=\dfrac{1}{2}m(v_{2}^2-v_{1}^2)[/tex]
Where, m = mass
[tex]v_{1}[/tex] = Initial velocity
[tex]v_{2}[/tex] = Final velocity
Put the value into the formula
[tex]E_{d}=\dfrac{1}{2}\times0.167\times(2.95^2-5.45^2)[/tex]
[tex]E_{d}=-1.7535\ J[/tex]
Negative sign shows the loss of energy.
Hence, The energy dissipated is 1.754 J.
