Answer:
Frequency of oscillation, f = 4 Hz
time period, T = 0.25 s
Angular frequency, [tex]\omega = 25.13 rad/s[/tex]
Given:
Time taken to make one oscillation, T = 0.25 s
Solution:
Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:
f = [tex]\frac{1}{T}[/tex]
f = [tex]\frac{1}{0.25}[/tex]
Frequency of oscillation, f = 4 Hz
The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.
Therefore, time period, T = 0.25 s
Angular frequency of oscillation is given by:
[tex]\omega = 2\pi \times f[/tex]
[tex]\omega = 2\pi \times 4[/tex]
[tex]\omega = 25.13 rad/s[/tex]
