Respuesta :
Answer:
a) The allele frequencies are - [tex]p= 0.8660\\q= 0.134[/tex]
b) Genotype frequencies for this population- [tex]p^2=0.75, q^2= 0.0179, 2pq = 0.2321[/tex]
Explanation:
Given ,
Red color of flower is dominant to white color flower
Let "R" represents allele for red color and "r" represents allele for white color
out of [tex]200[/tex] flower, [tex]150[/tex] are red flowers.
So the frequency of red flowers with genotype "RR" is equal to
[tex]p^{2} = \frac{150}{200} \\p^{2} =0.75[/tex]
As per hardy Weinberg's I equilibrium equation -
[tex]p+q=1\\p=\sqrt{p^2} \\p=\sqrt{0.75} \\p= 0.8660\\q= 1-p\\q= 1-0.8660\\q = 0.134[/tex]
a) The allele frequencies are - [tex]p= 0.8660\\q= 0.134[/tex]
Frequency of genotype "rr" i.e homozygous recessive white flower is
[tex]q^{2} \\0.134^2\\q^2 = 0.0179\\[/tex]
Substituting the values of [tex]p^2[/tex] and [tex]q^2[/tex], in below equation, we get -
[tex]p^2+2pq+q^2=1\\2pq= 1-p^2-q^2\\2pq= 1-0.75-0.0179\\2pq=0.2321[/tex]
b) Genotype frequencies for this population- [tex]p^2=0.75, q^2= 0.0179, 2pq = 0.2321[/tex]
