A circular cross section, d = 25 mm, experiences a torque load, T = 25 N·m, and a shear force, V = 85 kN. Calculate the largest shear stress within the cross section. B. 239 MPa A. 231 MPa C. 8.15 MPa D. 95.6 MPa

Respuesta :

Answer:

largest shear stress = 239 N/mm²

Explanation:

Given data

cross section d = 25 mm

torque load T = 25 N·m

shear force V = 85 kN

to find out

largest shear stress

solution

we know that maximum shear stress due to load = 16T / πd³

maximum shear stress = 16 ( 25) [tex]10^{3}[/tex] / π(25)³

maximum shear stress = 8.148 N/mm²    ........................1

maximum shear stress due to force = 14/3 × avg shear stress

maximum shear stress due to force = 14 × 85 ×[tex]10^{3}[/tex]  / (3 ×π/4×25²)

maximum shear stress due to force = 230.88 N/mm²    ..................2

so

largest shear stress add equation 1 and 2

largest shear stress = 8.148 + 230.88

largest shear stress = 239 N/mm²