Answer:
8.77×10⁻⁵ m
Explanation:
ω = angular velocity = 3.49 rad/s = 33 rpm
r = Radius of the groove = 0.1 m
f = Frequency = 3.98 kHz
Tangential Velocity of record
v = ωr
⇒v = 3.49×0.1
⇒v = 0.349 m/s
The velocity of the wave is 0.349 m/s
v = fλ
[tex]\lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{0.349}{3980}=8.77\times 10^{-5}\ m[/tex]
∴ Wavelength in the groove is 8.77×10⁻⁵ m
