Answer:
The atmospheric pressure is found to be [tex]104.378kPa[/tex]
Explanation:
We know that pressure exerted by a standing column of fluid is calculated using the equation
[tex]P=\rho _{fluid}\times gh[/tex]
In our case the pressure of the standing column of mercury is equal to the atmospheric pressure.
According to the given data we have
[tex]\rho _{fluid}=14000kg/m^{3}[/tex]
[tex]g=9.81m/s^{2}[/tex]
[tex]h=760mm=0.76m[/tex]
Using the values in the equation above we calculate atmospheric pressure to be
[tex]P_{atm}=14000\times 9.81\times 0.760\\\\=104.378kPa[/tex]