Answer:
There are 35990 ways in which 2 or 3 nodes fail
Step-by-step explanation:
Given : A computer network has 60 switching nodes.
To Find : In how many ways can 2 or 3 nodes fail?
Solution:
We are supposed to find no. of ways can 2 or 3 nodes fail.
So, we will use combination here .
No. of ways can 2 or 3 nodes fail=[tex]^{60}{C_2 +^{60}C_3[/tex]
Formula : [tex]^nC_r =\frac{n!}{r!(n-r)!}[/tex]
No. of ways can 2 or 3 nodes fail=[tex]\frac{60!}{2!(60-2)!}+\frac{60!}{3!(60-3)!}[/tex]
=[tex]35990[/tex]
Hence there are 35990 ways in which 2 or 3 nodes fail
