A lead acid battery with 12 cells connected in series (no-load voltage=2.1 volts per cell) furnishes 10 amperes to a load of 2-ohms resistance. The internal resistance of the battery in this instance is?

Respuesta :

Answer:

[tex]r = 0.043 ohm[/tex]

Explanation:

As we know that total potential of all cells when they are in series is given as

[tex]V = V_1 + V_2 + V_3 + ....................[/tex]

so we have

[tex]V_{net} = 12(2.1) = 25.2 Volts[/tex]

now total resistance of all 12 cells which are in series is given as

[tex]r_{net} = 12 r[/tex]

external resistance is given as

[tex]R = 2 ohm[/tex]

now by Ohm's law we know that

[tex]V_{net} = i (R + r_{net})[/tex]

so we have

[tex]25.2 = 10 (2 + 12 r)[/tex]

[tex]r = 0.043 ohm[/tex]