Answer:
K(maximum) = 0.284 eV
Explanation:
Given data
work function ω = 3.60 eV = 3.60 × 1.6 ×[tex]10^{-19}[/tex] = 5.76 ×[tex]10^{-19}[/tex] J
wavelength λ = 320 nm = 320 ×[tex]10^{-9}[/tex] m
to find out
maximum kinetic energy
solution
we know that speed of light is = 3 ×[tex]10^{8}[/tex] m/s
and planck constant h = 6.63 ×[tex]10^{-34}[/tex] J.s
we will apply here Einstein's photo elecric equation that is
hc/λ = ω + K(maximum)
put here all these value we get
6.63 ×[tex]10^{-34}[/tex] × 3 ×[tex]10^{8}[/tex] / 320 ×[tex]10^{-9}[/tex] = 5.76 ×[tex]10^{-19}[/tex] + K(maximum)
so
K(maximum) = 6.63 ×[tex]10^{-34}[/tex] × 3 ×[tex]10^{8}[/tex] / 320 ×[tex]10^{-9}[/tex] - 5.76 ×[tex]10^{-19}[/tex]
K(maximum) = 0.4556 ×[tex]10^{-19}[/tex] J
K(maximum) = 0.4556 ×[tex]10^{-19}[/tex] / 1.6 ×[tex]10^{-19}[/tex]
K(maximum) = 0.284 eV
