Respuesta :
Answer:
Accleration of masses = [tex]2.522m/s^{2}[/tex]
Tension in rope = 80.158 Newtons
Explanation:
Applying Newtons second law to both the masses we have
For 6.5 kg mass we have
[tex]T_{1}-6.5\times g=6.5\times a_{1}...................(i)[/tex]
Similarly for 11 kg mass applying Newton's second law yields
[tex]11\times g-T_{2}=11\times a_{1}...............(ii)[/tex]
Now since both the masses are connected by same string and the pulley is friction less the acceleration of both the masses shall be same and the tension in the string shall have unique value
thus solving equation i and ii by adding them we get
[tex]11g-6.5g=6.5a+11a\\\\\therefore a=\frac{11g-6.5g}{11+6.5}=0.257g\\\\a=0.257\times 9.81m/s^{2}=2.522m/s^{2}[/tex]
Using this value of accleration in any equation we obatin the value of tension as
[tex]T=6.5a+6.5g\\\\\therefore T=80.158Newtons[/tex]
