Respuesta :
Answer:
The magnetic field is 0.143 T in north direction.
Explanation:
Given that,
Length = 50 cm
Current = 7.0 A
Force = 0.5 N
We need to calculate the magnetic field
Using formula of magnetic force
[tex]\vec{F}I\vec{L}\times\vec{B}[/tex]
[tex]F=ILB[/tex]
[tex]B=\dfrac{F}{IL}[/tex]
[tex]B=\dfrac{0.5}{7.0\times50\times10^{-2}}[/tex]
[tex]B=0.143\ T[/tex]
The direction of the magnetic field toward north.
Hence, The magnetic field is 0.143 T in north direction.
Answer:
North, 0.1428 Tesla
Explanation:
As we know that the magnetic force in the wire can be calculated as,
[tex]F=Bilsin(\Theta )[/tex].
Here the uniform magnetic field is perpendicular to wire than theta will be 90°.
So the magnetic force will become,
[tex]F=Bil[/tex].
Substitute 50 cm for l, 7 A for i, and 0.5 N for F in the above equation.
[tex]B=\frac{0.5}{50\times 1`0^{-2} m(7 A) }\\B=0.1428 T[/tex]
Now according to Fleming's left hand law, if the current in the east ward direction and force is in upward direction then the value of magnetic field will be perpendicular to both in the north direction.
Therefore magnetic field will be 0.1428 T in the north direction.
