A series of five calibration standards 25, 50, 75 and 100 mg/L Potassium is required to be made from a 1000mg/L Potassium standard solution. If the final volume of the calibration standards is 100 mL, what is the required volume of the 1000 mg/L Potassium standard solution?

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Alleei Alleei · Answer 1 · 2019-08-27T06:59:22+02:00

Answer : The volume required is, 25 mL

Explanation :

First we have to determine the mass of potassium present in 100 mL or 0.1 L of each standards.

For 25 mg/L :

As, 1 L volume has mass of potassium = 25 mg

So, 0.1 L volume has mass of potassium = [tex]0.1\times 25=2.5mg[/tex]

For 50 mg/L :

As, 1 L volume has mass of potassium = 50 mg

So, 0.1 L volume has mass of potassium = [tex]0.1\times 50=5.0mg[/tex]

For 75 mg/L :

As, 1 L volume has mass of potassium = 75 mg

So, 0.1 L volume has mass of potassium = [tex]0.1\times 75=7.5mg[/tex]

For 100 mg/L :

As, 1 L volume has mass of potassium = 100 mg

So, 0.1 L volume has mass of potassium = [tex]0.1\times 100=10mg[/tex]

Now we have to determine the total mass of potassium.

Total mass of potassium = 2.5 + 5.0 + 7.5 + 10 = 25 mg

Now we have to determine the required volume of the 1000 mg/L Potassium standard solution.

As, 1000 mg mass of potassium present in 1 L volume

So, 25 mg mass of potassium present in [tex]\frac{25}{1000}=0.025L[/tex] volume

Volume required = 0.025 L = 25 mL (conversion used : 1 L = 1000 mL)

Therefore, the volume required is, 25 mL