Answer:
Speedd of the light in the medium is [tex]2.459\times 10^{8}m/s[/tex]
Explanation:
According to Snell's law we have
[tex]\mu _{1}sin(\theta _{i})=\mu _{2}sin(\theta _{r})[/tex]
Since incidence medium is air thus we have
[tex]\mu _{1}=1[/tex]
Applying values we get
[tex]1\times sin(63^{o})=\mu _{2}sin(47^{o})\\\\\therefore \mu _{2}=\frac{sin(63)}{sin(47)}=1.22[/tex]
Now we know that speed of light in any medium is given by
[tex]v=\frac{c}{\mu }[/tex]
where [tex]\mu [/tex] is the refractive index of the medium and 'c' is the speed of light in vacuum
Thus upon applying values we get
[tex]v=\frac{3\times 10^{8}}{1.22 }\\\\\therefore v=2.459\times 10^{8}m/s[/tex]
