contestada

In the F2 generation of a homozygous round (AA) × homozygous wrinkled (aa) cross in peas, three seeds are chosen at random. What is the probability that two seeds are round and the other is wrinkled?
A) (1/4)^3
B) 3(1/4)(3/4)^2
C) 3(1/4)^2(3/4)
D) (3/4)^3

Respuesta :

Answer:

Option B

Explanation:

First generation cross of homozygous round (AA) × homozygous wrinkled (aa) will give following offspring

Aa, Aa, Aa, Aa

F2 generation of a homozygous round (AA) × homozygous wrinkled (aa) cross in peas will give following offspring

Aa * Aa

AA, Aa, Aa, aa

If we consider that trait of round shaped seed is dominant over wrinkled shaped seed. Then out of four offspring AA, Aa, Aa, aa,

Probability of choosing a wrinkled seed is

[tex]\frac{1}{4}[/tex]

Probability of choosing a round  seed is

[tex]\frac{3}{4}[/tex]

So the probability that two seeds are round and the other is wrinkled is

[tex]3\frac{1}{4} * (\frac{3}{4})^2[/tex]

Hence, option B is correct

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