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An L−R−C series circuit has 91.5 Ω , and the amplitude of the voltage across the resistor is 36.0 V . What is the average power delivered by the source? Express your answer with the appropriate units.

Respuesta :

Answer:

14.16 W

Explanation:

We have given impedance Z=91.5 ohm

Voltage across the resistor = 36 V

We have to find the power delivered by the source

We know that according to telegens theorem , the absorbed = power delivered

So the voltage across the resistor = 36 V

Current in the RLC circuit [tex]i=\frac{V}{Z}=\frac{36}{91.5}=0.3934A[/tex] this current will be same in the whole circuit as it is a series RLC circuit

Now the power absorbed by the resistor [tex]P=i^2R=0.3934^2\times 91.5=14.16W[/tex]

As the power absorbed = power delivered

So power delivered by the source =14.16 W

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