Answer:
[tex]a_0=8\,,\,a_1=12[/tex]
Step-by-step explanation:
According to question, let smaller number be [tex]a_0[/tex] and larger number be [tex]a_1[/tex].
Given that sum of two numbers is 20 and difference is 4, we get equations as
follows:
[tex]a_0+a_1=20\\a_1-a_0=4[/tex]
From first equation , we get [tex]a_0=20-a_1[/tex]
On putting this in the second equation, we get
[tex]a_1-\left ( 20-a_1 \right )=4\\a_1-20+a_1=4\\2a_1-20=4\\2a_1=20+4\\a_1=12[/tex]
On putting [tex]a_1=12[/tex] in equation [tex]a_0=20-a_1[/tex], we get
[tex]a_0=20-a_1=20-12=8[/tex]
So, two numbers whose sum is 20 and difference is 4 are 12 and 8
