Respuesta :

Ashraf82

Answer:

one solution ⇒ 1st answer

Step-by-step explanation:

* Lets explain how to solve the question

- The 1st equation is 6x + 3y = 12

- The 2nd equation is y = 2x + 4

- To solve the two equation substitute y in the 1st equation by the

 2nd equation

∴ 6x + 3(2x + 4) = 12

- Multiply 3x by the bracket (2x + 4)

∴ 6x + 6x + 12 = 12

- Subtract 12 from both sides

∴ 12x = 0

- Divide both sides by 12

∴ x = 0

- Substitute the value of x in the 2nd equation

∴ y = 2(0) + 4

∴ y = 4

∴ The solution is (0 , 4)

* There is one solution for this system

tramserran

Answer:  ONE

Step-by-step explanation:

I am going to use substitution method to solve for x.

    6x + 3y = 12     and    y = 2x + 4

--> 6x + 3(2x + 4) = 12

    6x +  6x  +  12 = 12

            12x  +  12 = 12

            12x          = 0

               x           [tex]=\dfrac{0}{12}[/tex]

               x          = 0

Plug the x-value into y = 2x + 4 to solve for y:

y = 2(0) + 4

y =   0   + 4

y =           4

There is ONE solution, which is (0, 4)

Otras preguntas