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Professor armstrong weighed two pieces of metal for an experiment. The piece of iron weighed 12 1/3 pounds and the piece of aluminum weighed 10 2/3 pounds. How much more did the piece of iron weigh than the piece of aluminum

Respuesta :

lemickjac

Answer:

1  2/3

Step-by-step explanation:

This is simple subtraction.how much more means by what quantity is one greater than the other so we just find the difference.

Solution 1(long method)

we change the figures into improper fractions.

12 1/3 = 37/3

10 2/3 = 32/3

37/3 - 32/3 =5/3

5/3 to proper fraction = 1 2/3

Solution 2( use of a calculator)

12  1/3 - 10 2/3 = 1 2/3

If you need any clarification or more explanation pls do mention at the comment section.I would love to help more.

Hope this helps and if it does pls mark as branliest answer thx

carlosego

For this case we convert the mixed numbers into fractions:

[tex]12 \frac {1} {3} = \frac {3 * 12 + 1} {3} = \frac {36 + 1} {3} = \frac {37} {3}\\10 \frac {2} {3} = \frac {3 * 10 + 2} {3} = \frac {30 + 2} {3} = \frac {32} {3}[/tex]

If we subtract we have to:

[tex]\frac {37} {3} - \frac {32} {3} = \frac {5} {3} = 1.67[/tex]

IN mixed number [tex]\frac {5} {3} = 1 \frac {2} {3}[/tex]

Thus, the piece of iron weighs 1.67 pounds more than that of aluminum.

Answer:

1.67

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