A coil of 1,000 turns encloses an area of 85 cm^2. It is rotated in 0.090 s from a position where its plane is perpendicular to Earth's magnetic field to one where its plane is parallel to the field. If the strength of the field is 6.0 x 10^-5 T, what is the average emf induced in the coil (in mV)?

Respuesta :

Answer:

The average emf induced in the coil is [tex]5.6\times10^{-3}\ mV[/tex].

Explanation:

Given that,

Number of turns = 1000 turns

Area = 85 cm²

Time = 0.090 s

Its plane is perpendicular to Earth's magnetic field.

Angle = 0°

Magnetic strength [tex]B=6.0\times10^{-5}\ T[/tex]

We need to calculate the magnetic flux

Using formula of magnetic flux

[tex]\phi=BA\cos\theta[/tex]

Put the value into the formula

[tex]\phi=6.0\times10^{-5}\times85\times10^{-4}\times\cos0^{\circ}[/tex]

[tex]\phi =6.0\times10^{-5}\times85\times10^{-4}\times1[/tex]

[tex]\phi=5.1\times10^{-7}\ Wb[/tex]

We need to calculate the average emf induced in the coil

[tex]\epsilon=\dfrac{d\phi}{dt}[/tex]

Put the value into the formula

[tex]\epsilon=\dfrac{5.1\times10^{-7}}{0.090}[/tex]

[tex]\epsilon=0.0000056\ N[/tex]

[tex]\epsilon =5.6\times10^{-3}\ mV[/tex]

Hence, The average emf induced in the coil is [tex]5.6\times10^{-3}\ mV[/tex].