Answer:
E. 1.05
Explanation:
Angle of incidence= 45°
For blue light :
Using Snell's law as:
[tex]\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}[/tex]
Where,
Θ₁ is the angle of incidence
Θ₂ is the angle of refraction
n₁ is the refractive index for blue light which is 1.339
n₂ is the refractive index of air which is 1
So,
[tex]\frac {sin\theta_2}{sin{45.0}^0}=\frac {1.339}{1}[/tex]
[tex]{sin\theta_2}=0.9408[/tex]
Angle of refraction for blue light = sin⁻¹ 0.9408 = 71.20°.
For yellow light :
Using Snell's law as:
[tex]\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}[/tex]
Where,
Θ₁ is the angle of incidence
Θ₂ is the angle of refraction
n₁ is the refractive index for yellow light which is 1.330
n₂ is the refractive index of air which is 1
So,
[tex]\frac {sin\theta_2}{sin{45.0}^0}=\frac {1.330}{1}[/tex]
[tex]{sin\theta_2}=0.9406[/tex]
Angle of refraction for yellow light = sin⁻¹ 0.9406 = 70.15°.
The difference in the angle of refraction = 71.2° - 70.15° = 1.05°
