Answer:
So the fraction of proeutectoid cementite is 44.3%
Explanation:
Given that
cast iron with 0.35 % wtC and we have to find out fraction of proeutectoid cementite phase when cooled from 1500 C to room temperature.
We know that
Fraction of proeutectoid cementite phase gievn as
[tex]{w_p}'=\dfrac{{C_o}'-0.022}{0.74}[/tex]
Now by putting the values
[tex]{w_p}'=\dfrac{0.35-0.022}{0.74}[/tex]
[tex]{w_p}'=0.443[/tex]
So the fraction of proeutectoid cementite is 44.3%