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One railroad car rolls towards another. Describe the properties of the first car that determine its momentum and how it would impart an impulse to the second car.

Respuesta :

Answer:

Explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

The properties of the first car that determines its momentum is its mass and speed. The change in the speed of this first car after collision determines the impulse experienced by the by the second car.

The magnitude of the momentum of the cars is given by the following formulas;

P = mv

where;

  • m is the mass of the cars
  • v is the speed of the cars

The impulse impacted on the second car is determined using the following formula;

J = ΔP = mΔv

where

Δv is the change in the speed of the first car.

Thus, the properties of the first car that determines its momentum is its mass and speed. The change in the speed of this first car after collision determines the impulse experienced by the by the second car.

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