Answer:
Thus 16% of batteries fall below a life of 4.9 years.(Answer rounded to 1 decimal place)
Step-by-step explanation:
Taking normal distribution of shelf life we have
Given that mean life = 5 years
standard deviation = 0.1 years
Thus standard deviate factor 'Z' corresponding to an area of 16% = -0.994
thus we have
[tex]Z=\frac{X-\bar{X}}{\sigma }[/tex]
Applying values we get
[tex]-0.994=\frac{X-5}{0.1}\\\\\therefore X=5-0.994\times 0.1=4.90065[/tex]
Thus 16% of batteries fall below a life of 4.9 years.
