Respuesta :
Answer:
1. {198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997}
Mean of given numbers is:
[tex]Mean = \frac{Sum of all observations}{Total number of observation}[/tex]
[tex]=\frac{218+365+ 461+ 512+ 595+ 595+ 690+ 739+ 836+ 836+ 836+ 896+ 896+ 954+ 954}{15}[/tex]
= 692.2
For finding Median, firstly we arrange data in ascending or descending order: 218, 365, 461, 512, 595, 595, 690, 739, 836, 836, 836, 896, 896, 954, 954
Here number of terms is 15 which is odd.
So, Median = { (n + 1) ÷ 2 }th term
= { (15 + 1) ÷ 2 }th term
= [tex]8^{th}[/tex] term
= 739
For finding mode, We see the observation that has maximum number of frequency.
Here 836 is repeated 3 times and its frequency is maximum.
So, Mode = 836
Range = Highest value - Lowest value
= 954 - 218
= 736
2. {198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997}
Mean of given numbers is:
[tex]Mean = \frac{Sum of all observations}{Total number of observation}[/tex]
[tex]=\frac{198+ 212+ 262+ 284+ 313+ 488+ 602+ 602+ 606+ 616+ 616+ 678+ 754+ 937+ 997}{15}[/tex]
= 544.333
For finding Median, firstly we arrange data in ascending or descending order: 198, 212, 262, 284, 313, 488, 602, 602, 606, 616, 616, 678, 754, 937, 997
Here number of terms is 15 which is odd.
So, Median = { (n + 1) ÷ 2 }th term
= { (15 + 1) ÷ 2 }th term
= [tex]8^{th}[/tex] term
= 602
For finding mode, We see the observation that has maximum number of frequency.
Here 616 is repeated 2 times and its frequency is maximum.
So, Mode = 616
Range = Highest value - Lowest value
= 997 - 198
= 799
3. {199, 504, 584, 677, 690, 709, 740, 740, 805, 836, 839, 839, 873, 987, 994}
Mean of given numbers is:
[tex]Mean = \frac{Sum of all observations}{Total number of observation}[/tex]
[tex]=\frac{199+ 504+ 584+ 677+ 690+ 709+ 740+ 740+ 805+ 836+ 839+ 839+ 873+ 987+ 994}{15}[/tex]
= 734.4
For finding Median, firstly we arrange data in ascending or descending order: 199, 504, 584, 677, 690, 709, 740, 740, 805, 836, 839, 839, 873, 987, 994
Here number of terms is 15 which is odd.
So, Median = { (n + 1) ÷ 2 }th term
= { (15 + 1) ÷ 2 }th term
= [tex]8^{th}[/tex] term
= 740
For finding mode, We see the observation that has maximum number of frequency.
Here 839 is repeated 2 times and its frequency is maximum.
So, Mode = 839
Range = Highest value - Lowest value
= 994 - 199
= 795
4. {136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971}
Mean of given numbers is:
[tex]Mean = \frac{Sum of all observations}{Total number of observation}[/tex]
[tex]=\frac{136+ 238+ 320+ 403+ 434+ 553+ 555+ 571+ 571+ 581+ 723+ 824+ 857+ 948+ 971}{15}[/tex]
= 579
For finding Median, firstly we arrange data in ascending or descending order: 136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971
Here number of terms is 15 which is odd.
So, Median = { (n + 1) ÷ 2 }th term
= { (15 + 1) ÷ 2 }th term
= [tex]8^{th}[/tex] term
= 571
For finding mode, We see the observation that has maximum number of frequency.
Here 571 is repeated 2 times and its frequency is maximum.
So, Mode = 571
Range = Highest value - Lowest value
= 971 - 136
= 835
4. {136, 238, 320, 403, 434, 553, 555, 571, 571, 581, 723, 824, 857, 948, 971}
Mean of given numbers is:
[tex]Mean = \frac{Sum of all observations}{Total number of observation}[/tex]
[tex]=\frac{208+ 226+ 323+ 433+ 433+ 489+ 574+ 594+ 599+ 803 803+ 803+ 875+ 951+ 969}{15}[/tex]
= 605.5333
For finding Median, firstly we arrange data in ascending or descending order: 208, 226, 323, 433, 433, 489, 574, 594, 599, 803, 803, 803, 875, 951, 969
Here number of terms is 15 which is odd.
So, Median = { (n + 1) ÷ 2 }th term
= { (15 + 1) ÷ 2 }th term
= [tex]8^{th}[/tex] term
= 594
For finding mode, We see the observation that has maximum number of frequency.
Here 803 is repeated 3 times and its frequency is maximum.
So, Mode = 803
Range = Highest value - Lowest value
= 969 - 208
= 761
