Answer:
The time is 0.563 ns.
Explanation:
Given that,
Index of refraction of glass = 1.41
Distance = 12.0 cm
Angle = 33.0°
We need to calculate the refraction angle
Using Snell's law
[tex]n_{1}\sin\theta=n_{r}\sin\theta[/tex]
put the value into the formula
[tex]1\times\sin33=1.41\sin\theta[/tex]
[tex]\sin\theta=\dfrac{1\times\sin33}{1.41}[/tex]
[tex]\theta=22.71^{\circ}[/tex]
We need to calculate the velocity of beam in glass
Using formula of velocity
[tex]v=\dfrac{c}{n}[/tex]
Put the value into the formula
[tex]v=\dfrac{3\times10^{8}}{1.41}[/tex]
[tex]v=2.13\times10^{8}\ m/s[/tex]
We need to calculate the time
Using formula of distance
[tex]v=\dfrac{d}{t}[/tex]
[tex]t=\dfrac{12.0\times10^{-2}}{2.13\times10^{8}}[/tex]
[tex]t=5.63\times10^{-10}\ sec[/tex]
[tex]t=0.563\times10^{-9}\ sec[/tex]
[tex]t=0.563\ ns[/tex]
Hence, The time is 0.563 ns.
