Answer:
so his far point according to this pair of glass is 200 cm
Explanation:
power of old pair of corrective glasses is given as
[tex]P = -0.5 dioptre[/tex]
now we have
[tex]f = \frac{1}{P}[/tex]
[tex]f = -2 m[/tex]
[tex]f = -200 cm[/tex]
now we know that for normal vision the maximum distance of vision is for infinite distance
so by lens formula we have
[tex]\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}[/tex]
[tex]\frac{1}{d_i} + 0 = \frac{1}{200}[/tex]
[tex]d_i = 200 cm[/tex]
so his far point according to this pair of glass is 200 cm