Answer:
Maximum torque on the wire is [tex]1.34\times 10^{-4}\ N-m[/tex]
Explanation:
It is given that,
Diameter of the wire, d = 11.1 cm = 0.111 m
Radius of wire, r = 0.0555 m
Magnetic field, [tex]B=2.79\ mT=0.00279\ T[/tex]
Current, I = 5 A
We need to find the maximum torque on the wire. Torque is given by :
[tex]\tau=IAB\ sin\theta[/tex]
Torque is maximum when, [tex]\theta=90[/tex]
[tex]\tau=IAB[/tex]
[tex]\tau=5\times \pi \times (0.0555)^2\times 0.00279[/tex]
[tex]\tau=0.000134\ N-m[/tex]
or
[tex]\tau=1.34\times 10^{-4}\ N-m[/tex]
So, the maximum toque on the wire is [tex]1.34\times 10^{-4}\ N-m[/tex]. Hence, this is the required solution.
