Answer:
f(x)= −3x^2 + 4x + 6;
f(2) = 2;
f(3) = -9
Step-by-step explanation:
You have to substitute the values for the given functions. Remember to use PEDMAS for the order of operations: parentheses, exponents, division, multiplication, addition, and then substitution.
We'll insert 2 for the value of x for the first one.
f(2)= (-3)*2^2 + 4*2 + 6
f(2) = (-3)*4+ 4*2+6
f(2) = -12 + 8 + 6
f(2) = -12 + 14
f(2) = 2
We'll insert 3 for the value of x for the second one.
f(3) = (-3)*3^2+4*3+6
f(3) = (-3)*9+4*3+6
f(3) = -27 + 12 + 6
f(3) = -9
For this case we have the following function:
[tex]f (x) = - 3x ^ 2 + 4x + 6[/tex]
We must evaluate the function when[tex]x = 2[/tex]and[tex]x = 3[/tex]
For [tex]x = 2[/tex]:
[tex]f (2) = - 3 (2) ^ 2 + 4 (2) +6\\f (2) = - 3 * 4 + 8 + 6\\f (2) = - 12 + 8 + 6[/tex]
Different signs are subtracted and the major sign is placed.
Equal signs are added and the same sign is placed.
[tex]f (2) = - 4 + 6\\f (2) = 2[/tex]
For [tex]x = 3[/tex]:
[tex]f (3) = - 3 (3) ^ 2 + 4 (3) +6\\f (3) = - 3 * 9 + 12 + 6\\f (3) = - 27 + 12 + 6[/tex]
Different signs are subtracted and the major sign is placed.
Equal signs are added and the same sign is placed.
[tex]f (3) = - 15 + 6\\f (3) = - 9[/tex]
Answer:
[tex]f (2) = 2\\f (3) = - 9[/tex]
