Sunlight passes through a couple of polarizers. If the transmitted brightness is 20% of the sunlight brightness, calculate the angle, rounded to the nearest tens of degrees, between the polarizers. A. 20° B. 30° OC. 40 D. 50° E. 60°

Respuesta :

Answer:

option D= 50°

Explanation:

When sunlight passes through the first polarizer, the intensity reduces to its half

that is [tex]I_1=0.5I_o[/tex].........(1)

let the angle between the polarizers be θ

then we know that the intensity of light after passing through second polarizer is

[tex]I_2=I_1 cos\theta[/tex]

⇒[tex]I_2= 0.5I_o cos^2\theta[/tex]............(2)    from (1)

also given that [tex]I_2=0.2I_o[/tex]..............(3)

equating 2 and 3 we get

[tex]0.2I_o=0.5I_ocos^2\theta[/tex]

on solving the above equation we get

θ= 50.75°≅50°

hence the angle between polarizers is 50°

option D is correct