Respuesta :
Answer:
Lead metal has a greater magnitude of temperature change.
Explanation:
let the mass of copper and lead be m.
Energy loosed by Copper metal = -Q = -100 J
(Negative sign just indicates that energy is released)
Change in temperature warm of the copper =[tex]\Delta T[/tex]
Specific heat capacity of copper = c = 0.093 KCal/Kg°C = 389.112 J/kg°C
1 kCal = 4184 Joules
[tex]Q=mc\Delta T[/tex]
[tex]-100 J=m\times 389.112 J/kg^oC\times \Delta T[/tex]
[tex]100=m\times 389.112 J/kg^oC\times \Delta T[/tex]
[tex]\Delta T=\frac{0.2569}{m}[/tex]
Energy gained by lead metal = Q' = 100 J
Change in temperature lead=[tex]\Delta T'[/tex]
Specific heat capacity of lead = c' = 0.031 KCal/Kg°C = 129.704 J/kg°C
[tex]Q=mc\Delta T[/tex]
[tex]100 J=m\times 129.704 J/kg^oC\times \Delta T'[/tex]
[tex]\Delta T'=\frac{0.7709}{m}[/tex]
On comparing temperature changes in both metals:
[tex]\frac{0.2569}{m},\frac{0.7709}{m}[/tex]
[tex]\frac{0.2569}{m}<\frac{0.7709}{m}[/tex]
[tex]\Delta T<\Delta T'[/tex]
Lead metal has a greater magnitude of temperature change.
