Respuesta :

Answer:

Step-by-step explanation:

Ver imagen amy16084

[tex]\bf \Delta x = (v_ot)+\left( \cfrac{1}{2}at^2 \right)\implies \Delta x = v_ot+\cfrac{at^2}{2}\implies \Delta x -\cfrac{at^2}{2}=v_ot \\\\\\ \cfrac{2\Delta x - at^2}{2}=v_ot\implies \cfrac{2\Delta x - at^2}{2v_o}=t[/tex]