What is the value of the boltzmann constant of 1.7 moles of gas at 290 K that has an average kinetic energy of 1.4 MJ? A. 7x10^-24 J/K
B. 1.4x10^-23 J/K
C. 6x10^-3 J/K
D. 7x10^-3 J/K

Respuesta :

Answer:

The value of  of the Boltzmann constant is [tex]3.14\times 10^{-23} J/K[/tex].

Explanation:

Generally the formula for average kinetic energy of a molecule :

[tex]K.E=\frac{3}{2}kT[/tex]

where,

k = Boltzmann’s constant

T = temperature = 290 K

Given:

Number of molecules in 1.7 moles:

[tex]1.7\times 6.022\times 10^{23} molecules=1.0237\times 10^{24} molecules[/tex]

Average kinetic energy of 1.7 moles = 1.4 MJ =[tex]1.4\times 10^6 J[/tex]

Average kinetic energy of 1 molecule = [tex]\frac{1.4\times 10^6 J}{1.023\times 10^{24}} =1.3675\times 10^{-18} J[/tex]

[tex]1.3675\times 10^{-18} J=\frac{3}{2}\times k\times (290K)[/tex]

[tex]k=3.14\times 10^{-23} J/K[/tex]