Answer:
Magnification, m = -0.42
Explanation:
It is given that,
Height of diamond ring, h = 1.5 cm
Object distance, u = -20 cm
Radius of curvature of concave mirror, R = 30 cm
Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)
Using mirror's formula :
[tex]\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}[/tex], f = focal length of the mirror
[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}[/tex]
v = -8.57 cm
The magnification of a mirror is given by,
[tex]m=\dfrac{-v}{u}[/tex]
[tex]m=\dfrac{-(-8.57)}{-20}[/tex]
m = -0.42
So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.
