Answer:
Ole was at loss of $0.5142.
Explanation:
Volume of the gas at 65.3°F =[tex]V_1=2.50 gal[/tex]
Volume of gas at 10.5°F =[tex]V_2=?[/tex]
Fahrenheit to Kelvin conversion:
[tex]((T)F- 32)\times \frac{5}{9} + 273.15 = (T)K[/tex]
[tex]T_1=65.3^oF=291.65 K[/tex]
[tex]T_2=10.5^oF=261.2056 K[/tex]
Using Charles law: Volume of gas is directly related to temperature of the gas under constant pressure.
[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]
[tex]V_2=\frac{2.50 gal\times 261.2056 K}{291.65 K}=2.2390 gal[/tex]
Cost of 1 gal of gas = $1.97
Cost of 2.50 gal of gas = 2.50 × $1.97 =$4.925
Cost of 2.2390 gal of gas = 2.2390 × $1.97 =$4.4108
Loss of money = $4.925 - $4.4108 = $0.5142
