Answer:
Momentum of a photon, [tex]P=1.13\times 10^{-27}\ kg-m/s[/tex]
Explanation:
It is given that,
The frequency of light, [tex]f=5.09\times 10^{14}\ Hz[/tex]
We need to find the momentum of a photon. The relation between momentum and wavelength is given by :
[tex]P=\dfrac{h}{\lambda}[/tex]
Since, [tex]\lambda=\dfrac{c}{f}[/tex]
[tex]P=\dfrac{fh}{c}[/tex], c is the speed of light
[tex]P=\dfrac{5.09\times 10^{14}\times 6.67\times 10^{-34}}{3\times 10^8}[/tex]
[tex]P=1.13\times 10^{-27}\ kg-m/s[/tex]
So, the momentum of a photon is [tex]1.13\times 10^{-27}\ kg-m/s[/tex]. Hence, this is the required solution.
