Answer:
five and one third + 2x ≥ 7
Step-by-step explanation:
Let
x -----> the minimum number of hours he needs to practice on each of the two days
we know that
Julian needs to spend at least seven hours each week practicing the drums
so
[tex]5\frac{1}{3}+2x\geq 7\ hours[/tex]
Convert mixed number to an improper fraction
[tex]5\frac{1}{3}\ hours=\frac{5*3+1}{3}=\frac{16}{3}\ hours[/tex]
substitute
[tex]\frac{16}{3}+2x\geq 7[/tex]
Subtract 16/3 both sides
[tex]2x\geq 7-\frac{16}{3}[/tex]
[tex]2x\geq \frac{5}{3}[/tex]
Divide by 2 both sides
[tex]x\geq \frac{5}{6}[/tex]
therefore
The minimum number of hours he needs to practice on each of the two days is [tex]\frac{5}{6}\ hours[/tex]
Answer: Fourth option is correct.
Step-by-step explanation:
Since we have given that
Atleast number of hours each week practicing the drums = 7
Number of hours he already practiced = [tex]5\dfrac{1}{3}[/tex]
Let the number of hours left be x.
it splits the remaining practice time between the last two days.
So, it becomes,
[tex]5\dfrac{1}{3}+2x\geq 7\\\\\dfrac{16}{3}+2x\geq 7\\\\2x\geq 7-\dfrac{16}{3}\\\\2x\geq \dfrac{21-16}{3}\\\\2x\geq \dfrac{5}{3}\\\\x\geq \dfrac{5}{6}[/tex]
Hence, Fourth option is correct.
